Given volume of water produced in the reaction = 74.7 mL
Density of water = 0.987 g/mL
Calculating the mass of water = [tex] 74.7 mL * 0.987 g/mL = 73.73 g [/tex]
Moles of water produced = [tex] 73.73 g H_{2}O * \frac{1 mol H_{2}O}{18.02 g H_{2}O} = 4.09 mol H_{2}O [/tex]
The balanced chemical equation between nitric acid and magnesium hydroxide is,
[tex] 2 HNO_{3}(aq) + Mg(OH)_{2}(aq) --> 2 H_{2}O(l) + Mg(NO_{3})_{2} (aq) [/tex]
1 mol Magnesium hydroxide gives 2 mol water.
Moles of Magnesium hydroxide = [tex] 4.09 mol H_{2}O * \frac{1 mol Mg(OH)_{2}}{2 mol H_{2}O} = 2.045 mol Mg(OH)_{2} [/tex]
