The angular velocity of the bicycle if its angular acceleration is constant, and the acceleration and velocity have the same direction is 1.60 rad/s.
The angular velocity of a body is the rate by which the body changed its angle with respect to the time. It can be given as,
[tex]\omega= \dfrac{\Delta \theta}{\Delta t}[/tex]
The angular acceleration is rate of change of angular speed with time. It can be given as,
[tex]a=\dfrac{\Delta\omega}{t}\\a=\dfrac{\omega-\omega_o}{t}\\\omega=\omega_o+at[/tex]
It is given that the, angular acceleration is constant and equal to 0.200 rad/s2 and time is 2.50s. The initial velocity of the bicycle is given 1.10 rad/s.
Here, the acceleration and velocity have the same direction. Thus, the angular velocity is,
[tex]\omega=\omega_o+at\\\omega=1.10+0.200(2.5)\\\omega=1.60\rm \;rad/s[/tex]
Hence, the angular velocity of the bicycle if its angular acceleration is constant, and the acceleration and velocity have the same direction is 1.60 rad/s.
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