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gamechanger999
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♦__Let

d = the no of dimes (not the value)

q = the no of quarters (not the value)

since we have 2 unknowns we need 2 equations

 

equations

d + q = 103 

0.10d + 0.25q = 15.25  [the value of the coins times the no of coins equals $15.25]

 

 

d = 103 -q   [solving one equation for d and then substituting it into the other]

 

0.10(103 -q) + 0.25q = 15.25

 

10.3 - 0.10q + 0.25q = 15.25

 

0.15q = 4.95

q = 33 There are 33 quarters.
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HOPE IT HELPS!!✌✌✔✔

The value of the coins of dimes is 70 and quarters is 33

Given that,

A collection of dimes and quarters is worth 15.25. there are 103 coins in all.

We have to determine,

How many of each are there?

According to the question,

Let the number of coins of dimes be (103-x)

The value of dimes = 0.10(103-x)

And the number of coins of quarters be q.

The value of the quarters is x

A collection of dimes and quarters is worth 15.25.

[tex]\rm 0.25x+0.10(103-x)=$15.25[/tex]

Solving the equation for the value of x,

[tex]\rm 0.25x+0.10(103-x)=$15.25\\\\0.25x+10.3-0.10x=15.25\\\\0.15x = 15.25-10.3\\\\0.15x= 4.95\\\\x = \dfrac{4.95}{0.15}\\\\\rm x=33[/tex]

Therefore,

The value of dimes is,

[tex]\rm = 103-x\\\\=103-33\\\\= 70[/tex]

And The value of the quarters is x = 33.

Hence, The value of the coins of dimes is 70 and quarters is 33.

To know more about Equation click the link given below.

https://brainly.com/question/346207

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