Answer:
Difference in potential energy is, [tex]\Delta V=-4.6\times 10^{-16}[/tex]
Explanation:
It is given that,
Charge, [tex]q=1.3\times 10^{-16}\ C[/tex]
It moves from potential A to a lower potential B
Electric field, [tex]E=3.2\times 10^2\ N/C[/tex]
Distance travelled, [tex]r=1.1\times 10^{-2}\ m[/tex]
We have to find the difference in potential energy. We know that the work done is stored in the form of potential energy.
Also, [tex]\Delta V=\dfrac{\Delta U}{q}[/tex]
[tex]\Delta U[/tex] is potential energy
And [tex]E=-\dfrac{dV}{dr}[/tex]
So, [tex]W=-qEr[/tex]
[tex]W=-1.3\times 10^{-16}\times 3.2\times 10^2\times 1.1\times 10^{-2}[/tex]
[tex]W=-4.576\times 10^{-16}\ J[/tex]
[tex]W=-4.6\times 10^{-16}\ J[/tex]
Hence, the difference in potential energy is "-4.6 × 10⁻¹⁶ J"
